Two-Level Systems by Hand — Why levels refuse to cross
Exercises
Introductory Quantum Mechanics › Unit 3 · Two-level systems & spin-1/2 › Two-Level Systems by Hand › all problems
Why levels refuse to cross
Solution
A degeneracy of a real symmetric 2×2 block requires TWO conditions to hold at once: and — the square root vanishes only when both do. A single knob traces a one-parameter path through the plane, and a path generically misses the single point where two conditions hold: degeneracies have codimension 2 (three, for complex Hermitian, where Re and Im of the coupling must both vanish). This is the von Neumann–Wigner counting: crossings seen along one-parameter sweeps are infinitely fine coincidences, so what one actually observes is approach-and-repel, with the minimum gap set by whatever coupling refuses to vanish.
The exception is a symmetry. If the two states carry different quantum numbers of an operator commuting with (different parity, different angular momentum projection, different particle number), then identically — not by tuning but by theorem — and one condition remains: , reachable with one knob. Crossings between different-symmetry levels are allowed and common; crossings within a symmetry class are forbidden and avoided. Reading a level diagram is therefore symmetry spectroscopy: every avoided crossing announces a coupling, every true crossing announces a conserved quantum number distinguishing the pair.